=10/17+-5/13+7/17+-8/13+-11/25

=1+-1+-11/25

=11/25

b , 

= 1+-2+3+-4+5+-6+......2011+-2012

=1+1+1+1+1.........+-2012

=1.2011+-2012

=2011+-2012

=-1

2.

2/3-x = 5/4

=>x=2/3-5/4

=>x=-7/12

b,

[124-(20-4x)]:30+7=11

=>124-(20-4x)] :30 =11-7

=>[124-(20-4x)]:30=4

=>124-(20-4x)=4x30

=>124-(20-4x)=120

=>20-4x=120-124

=>20-4x=4

=>4x=20-4

=>4x=16

=>x=16:4

=>x=4

bài 1 

a, ghép cặp phân số 10/17 + 7/17 và 5/13 + -8/13 

b, 1-2+3-4+5-6+.....+2011-2012

= ( 1-2) + ( 3-4) + ( 5-6) +....+(2011-2012)

= (-1) + (-1) + (-1) + ....+ (-1)

< từ 1 đến 2012 có 2012 số số hạng, suy ra có 1006 cặp mà mỗi cặp có giá trị = (-1) Suy ra tổng trên = (-1) * 1006=-1006

Bài 2:

a,2/3 - x =5/4

          x=2/3 - 5/4

           x= -7/12

\(a.\)

\(\frac{15}{33}+\frac{7}{20}+\frac{18}{33}+\frac{13}{20}\)

\(=\left(\frac{15}{33}+\frac{18}{33}\right)+\left(\frac{13}{20}+\frac{7}{20}\right)\)

\(=\frac{33}{33}+\frac{20}{20}\)

\(=1+1=2\)

\(b.\)

\(2\frac{1}{2}+\frac{4}{7}:\left(-\frac{8}{21}\right)\)

\(=\frac{5}{2}+\frac{4}{7}:\left(-\frac{8}{21}\right)\)

\(=\frac{5}{2}+\frac{4}{7}.\left(-\frac{21}{8}\right)\)

\(=\frac{5}{2}+\frac{1}{1}.\left(-\frac{3}{2}\right)\)

\(=\frac{5}{2}-\frac{3}{2}\)

\(=1\)

\(c.\)

\(\left(-\frac{1}{2}\right)^3+\frac{1}{2}:5\)

\(=-\frac{1}{8}+\frac{1}{2}.\frac{1}{5}\)

\(=-\frac{1}{8}+\frac{1}{10}\)

\(=-\frac{1}{40}\)

a) \(\frac{15}{33}+\frac{7}{20}+\frac{18}{33}+\frac{13}{20}=\left(\frac{15}{33}+\frac{18}{33}\right)+\left(\frac{7}{20}+\frac{13}{20}\right)\) = 1 + 1 = 2

b) \(2\frac{1}{2}+\frac{4}{7}:\left(\frac{-8}{21}\right)=\frac{5}{2}+\frac{4}{7}:\left(\frac{-8}{21}\right)=\frac{5}{2}+\frac{-3}{2}\) = 1

c) \(\left(\frac{-1}{2}\right)\)³ + \(\frac{1}{2}\) : 5 = \(\frac{-1}{8}+\frac{1}{10}\) = \(\frac{-1}{40}\)

Chúc bạn học tốt!

b) \(\frac{\frac{2}{3}+\frac{5}{7}+\frac{4}{21}}{\frac{5}{6}+\frac{11}{7}-\frac{7}{21}}\)

\(=\frac{\frac{29}{21}+\frac{4}{21}}{\frac{101}{42}-\frac{7}{21}}\)

\(=\frac{\frac{11}{7}}{\frac{29}{14}}\)

\(=\frac{22}{29}.\)

Chúc bạn học tốt!

bai de the ma cung hoi

a)

i.Ta có: BCNN(12, 30) = 60

60 : 12 = 5; 60 : 30 = 2. Do đó:

\(\frac{5}{{12}} = \frac{{5.5}}{{12.5}} = \frac{{25}}{{60}}\) và \(\frac{7}{{30}} = \frac{{7.2}}{{30.2}} = \frac{{14}}{{60}}.\)

ii.Ta có: BCNN(2, 5, 8) = 40

40 : 2 = 20; 40 : 5 = 8; 40 : 8 = 5. Do đó:

\(\frac{1}{2} = \frac{{1.20}}{{2.20}} = \frac{{20}}{{40}}\)

\(\frac{3}{5} = \frac{{3.8}}{{5.8}} = \frac{{24}}{{40}}\)

\(\frac{5}{8} = \frac{{5.5}}{{8.5}} = \frac{{25}}{{40}}\).

b)

i.Ta có: BCNN(6, 8) = 24

24 : 6 = 4; 24: 8 = 3. Do đó

\(\begin{array}{l}\frac{1}{6} + \frac{5}{8} = \frac{{1.4}}{{6.4}} + \frac{{5.3}}{{8.3}}\\ = \frac{4}{{24}} + \frac{{15}}{{24}} = \frac{{19}}{{24}}.\end{array}\)

ii. Ta có: BCNN(24, 30) = 120

120: 24 = 5; 120: 30 = 4. Do đó:

\(\begin{array}{l}\frac{{11}}{{24}} - \frac{7}{{30}} = \frac{{11.5}}{{24.5}} - \frac{{7.4}}{{30.4}}\\ = \frac{{55}}{{120}} - \frac{{28}}{{120}} = \frac{{27}}{{120}} = \frac{9}{{40}}\end{array}\)

M=3/1.2-5/2.3+7/3.4-9/4.5+11/5.6-13/6.7+15/7.8+17/8.9

   =(1/1.1+2/1.2)-(2/2.3+3/2.3)+(3/3.4+4/3.4)-(4/4.5+5/4.5)+...+(8/8.9+9/8.9)(phần ... là làm tương tự nhé)

   =1/2+1-(1/3+1/2)+(1/4+1/3)-(1/5+1/4)+...+(1/9+1/8)(phần ... là làm tương tự nhé)

   =1+(1/2-1/2)+(1/3-1/3)+(1/4-1/4)+...+(1/8-1/8)-1/9

   =1+0+0+0+...+0-1/9

   =1-1/9

   =8/9

Bài 1 mik học xong quên hết òi (mấy bài kia là hok biết luôn :V)

B= \(\frac{1}{2}+\frac{1}{6}+\frac{1}{12}+\frac{1}{20}+\frac{1}{30}+\frac{1}{42}\)

B=\(\frac{1}{1.2}+\frac{1}{2.3}+\frac{1}{3.4}+\frac{1}{4.5}+\frac{1}{5.6}+\frac{1}{6.7}\)

B=1-\(\frac{1}{2}+\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+\frac{1}{5}-\frac{1}{6}+\frac{1}{6}-\frac{1}{7}\)

B=1-1/7

B=6/7